$\frac{dx}{dt}=\frac{t^2+1}{x^2+1}$
$x^5\:-\:2x^4\:-\:2x^3\:+\:5\::\:2x^3\:-\:2x^2\:+\:x\:-\:1$
$4^2-\left(-3^2\right)$
$20\:por\:12$
$\int6x^5dx$
$\int\left(-x\sin\left(4x\right)\right)dx$
$\frac{x}{x-1}\ge\frac{1}{x-1}$
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