$f\left(x\right)=4x^{3}\text{find}f^{1\prime\prime}$
$y^4-169$
$\frac{3}{\text{4}}\left(x-1\right)<\left(x+2\right)$
$\frac{18^{10}}{9^{10}}-1020$
$\left(\frac{9}{5}-\frac{-12}{5}-\frac{1}{5}\right)$
$5.4\left(-1\right)$
$\sqrt{3x+3}=0$
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