$-\frac{60}{6}$
$5x\:+\:10\:<12x-4$
$22+5-3^2-3$
$x+4=20$
$2\left(\frac{t^2}{20}-2\right)^2+2$
$\ln\left(2x^2-3x+1\right)$
$0=e^{-x^2}$
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