$\left(9x-5-x^2\right)^2$
$0.335=\tan\left(x\right)+\left(64\left(\tan\left(x\right)^2\right)\right)$
$x^2+7x=-6$
$\frac{\left(2a+9b\right)}{3}$
$500\cdot\left(-4\right)$
$\left(r^3+2s^3\right)^3$
$\int\frac{1}{3x^2+12}dx$
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