$6s+3t-21r$
$\lim_{x\to0}\left(\frac{5x}{\ln\left(2+e^x\right)}\right)$
$4x^2+16x+16y=0$
$x^{-2}y^{-1}dx+x^{-2}y^{-4}dy=0$
$sec^2b\:+\:tan^2+10=\frac{2}{cos^2\:\:b}$
$\lim_{x,y\to0,0}\frac{\left(y^2-x\right)^2}{x^2+y^2}$
$3x-6x+4$
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