$x^2\frac{dy}{dx}=\sqrt{y}\left(2x+5\right)$
$y=\left(4x^3+x^2\right)^2$
$3+\frac{3}{1}$
$\frac{5x^2+20x+16}{x+3}$
$0.624+18.346$
$6\left(4x+9\right)-8\left(5x-8\right)$
$x-10>1$
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