$4\left(2x^2-1\right)^2-2\left(2x^2-1\right)$
$x-5=-9$
$\lim_{x\to0}\left(1-\sqrt[3]{1-x}\right)$
$-5.4-\left(-2.3\right)$
$3^{-5}\cdot3^6$
$\frac{x^2+6x+12}{x+2}<\:1$
$4x^4+32x^2+64$
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