$3x\left(x-5\right)^6$
$6r^2\:-\:5r^5\:-\:5r^4\:+\:12r$
$36+12m^2m^4$
$\frac{x^3+2x^2-3x+4}{x^2+5x+6}$
$19x+3x^2+2x-x^2-10x+5x^2$
$\sqrt{3by^2}$
$6xy+10xz$
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