$5x-3\left(x-4\right)=60$
$xy^2=16$
$3\cdot1^2-5\cdot1+2$
$y'\:+\:2x^2\:+\:3y\:=\:0$
$9+8\cdot\left(3-5\right)+9$
$\frac{d}{dx}7\sqrt{8x^2}$
$\int_{-\infty}^{-3}\left(x^{-3}\right)dx$
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