$\frac{1-\cos\left(x\right)}{\sec\left(x\right)-1}=\cos\left(x\right)$
$2x^2+4x+4$
$8^{x-4}=8^{10}$
$\left(4y^2-z^n\right)^2$
$\lim_{x\to0}\left(\frac{6sinx}{1-secx}\right)^2$
$4x-3y^2\cdot y=0$
$100x^12-60x^6\:y^3+9y^6$
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