$1.18y^2+0.47y$
$\frac{dy}{dx}=\left(\frac{-2}{20-x}\right)y+0.8$
$y^2=-6y-9$
$\int\frac{3x^3+3x^2+3x-3}{x^2-1}dx$
$-3x^2-\:3x^2-3x^2$
$-\left(1+7x\right)-6\left(-7-x\right)$
$\left(7x-8y\right)^3$
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