$k^2+8k=0$
$4-x<x+10$
$\int\frac{x}{16x^4}-1dx$
$\left(sin\:\left(x\right)-\:cos\:\left(x\right)\right)\left(sin\:\left(x\right)\:+\:3cos\left(x\right)\right)=0$
$\frac{3-x\left(x+2\right)}{54}$
$\lim_{x\to\infty}\:\frac{2x^3+3x^2+x}{2x^3}$
$\lim_{x\to3}x^3+2x-9$
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