$\int\frac{\left(e^{x+3}\right)}{\left(e^{2x}-9\right)}\:dx$
$27\left(-3\right)-\left(3\right)\cdot\left(-5\right)-\left(-6\right)\cdot\left(-2\right)$
$\left(-9\right).0$
$5ab^4\left(12b-21a\right)$
$3\left(8p\right)$
$x-17=22$
$3m^2+m^3$
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