$\lim_{x\to-1}\left(\frac{\ln\left(2+x\right)}{x+1}\right)$
$3x^2-2x-8=0$
$-x+2=0$
$x^6+2x^4-16x^2-32$
$14-\left(-29\right)$
$\frac{20x^6y^5-12x^5y^4-8x^3y^3}{-2x^2y^3}$
$1312^3$
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