$\left(2z-3w\right)^2$
$x^5-40x^3+144x$
$2\cdot1+3\cdot0.5$
$\frac{dy}{dx}y=\left(\frac{98}{\left(x^2+49\right)}\right)$
$2x^3-18x+24$
$-8^0$
$\left(\:x+2y\right)\:\left(2y-x\right)$
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