$-12a+4-10a$
$x^2+9x-10=0$
$12x<6x+12\:$
$\int\frac{x}{\left(x+1\right)\left(x^2-1\right)}dx$
$\int\frac{\left(x-2\right)\left(2x+1\right)}{x}dx$
$3\left(\sin\left(x\right)\right)^2-7\sin\left(x\right)+2=0$
$\frac{dy}{dx}=3\left(x-2\right)^2$
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