$x^2+2x-3\cdot x^2+3x-4$
$\frac{d}{dx}\sqrt{\frac{x-3}{x^6+4}}$
$\frac{\tan x}{\sec x-1}-\frac{\tan x}{1+\sec x}=2\sin x$
$\frac{3^2\cdot5^4}{0.9^3}$
$x^3+2x\:-x^3$
$3x-y=-13\:\:\:$
$y'\:+\:5x^4y\:=\:x^4$
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