$\lim_{x\to\infty}\left(\frac{x-3}{x^2-6x+9}\right)$
$9n^2-6nu+u^2$
$\left(2\cdot4+12\right)\left(6-4\right)$
$\frac{x^5+x^3+1}{x+1}$
$\frac{d}{dx}\frac{y}{\sqrt{xy}}$
$\lim_{x\to2}\left(\frac{x^2-7}{\sqrt{2}-\sqrt{x}}\right)$
$\tan^23x=1$
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