$3x+8=35$
$\lim_{x\to0}\left(\frac{e^x\sin\left(x\right)-e^x\cos\left(x\right)}{\sin^2\left(x\right)}\right)$
$h\left(z\right)=\left(6-z^2\right)\left(z^3-5z+3\right)$
$2\left(-2\right)^3-4\left(-2\right)^2+6\left(-2\right)-8$
$4+-5+-1+-8$
$\frac{4x-2}{5}+\frac{x+1}{2}>4$
$140\cdot5$
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