$\frac{3^7\cdot3^3\cdot6^2\cdot6^5}{6^4\cdot3^8}$
$\left(b-2\right)\left(b+5\right)$
$\int\frac{3x^3+x}{\left(x+1\right)^2}dx$
$xy^2=\left(x^2+y^2\right)^2$
$\left(7x+2y\right)\left(7x-2z\right)$
$\left(3ax+z^2\right)^2\left(3ax+z^2\right)$
$12,08\:+\:9,07$
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