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# Simplify the quotient of powers $\frac{\sqrt{2x^{12}y^{21}z^8}}{40\sqrt{xyz}}$

## Step-by-step Solution

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### Videos

$\frac{\sqrt{2}y^{10}\sqrt{x^{11}}\sqrt{z^{7}}}{40}$
Got another answer? Verify it here

## Step-by-step Solution

Problem to solve:

$\frac{\sqrt{2x^{12} y^{21} z^8}}{40\sqrt{xy\cdot z}}$

Choose the solving method

1

The power of a product is equal to the product of it's factors raised to the same power

$\frac{\sqrt{2x^{12}y^{21}z^8}}{40\sqrt{x}\sqrt{yz}}$

Learn how to solve quotient of powers problems step by step online.

$\frac{\sqrt{2x^{12}y^{21}z^8}}{40\sqrt{x}\sqrt{yz}}$

Learn how to solve quotient of powers problems step by step online. Simplify the quotient of powers ((2x^12y^21z^8)^0.5)/(40(xyz)^0.5). The power of a product is equal to the product of it's factors raised to the same power. The power of a product is equal to the product of it's factors raised to the same power. The power of a product is equal to the product of it's factors raised to the same power. The power of a product is equal to the product of it's factors raised to the same power.

$\frac{\sqrt{2}y^{10}\sqrt{x^{11}}\sqrt{z^{7}}}{40}$
SnapXam A2

### beta Got another answer? Verify it!

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1
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7
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9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

$\frac{\sqrt{2x^{12} y^{21} z^8}}{40\sqrt{xy\cdot z}}$