$\int\left(\frac{x}{\left(1+2x^2\right)^2}\right)dx$

$23x^3-5x^2$

$\left(2+y\right)^2+\left(2+y\right)\cdot y=12$

$\left(x+4\right)\left(x-4\right)+\left(x+5\right)\left(x-5\right)-2\left(x+2\right)\left(x-3\right)$

$7^3+x^2-7x^3-8x+12$

$\frac{dy}{dx}=-6e^{x+8y}$

$\int\:\frac{2x^2}{\sqrt[3]{-1-x^3}}\:dx$