$\frac{1}{2}ab+\frac{2}{3}ab$
$\int-14\left(3x+2\right)cos\left(4x\right)dx$
$\left(a^3b^2\right)^2\left(a^4b\right)^{-3}$
$\frac{dy}{dx}=\tan\left(4\cdot x\right)$
$\lim_{x\to0}\left(\frac{cosnx}{cosmx}\right)$
$\frac{-108}{18}$
$\frac{2x+3}{\:5x}\le1$
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