$v^2+12v$
$4d^2+14d+12$
$\int\frac{x^6-x^3}{x^4+9x^2}dx$
$\left(x-\sqrt{2}\right)\left(x+\sqrt{2}\right)\left(x+1\right)$
$\left(6x^3-y^2\right)^2$
$-3\left(x+9\right)=15$
$\sqrt { x + 16 } - \sqrt { x } = - 2$
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