$2x^2+7x+3=0$

$\frac{d}{dx}\frac{in\:x}{x}$

$\left(\left(1+x\right)\cdot\left(1-x\right)\right)^4$

$\lim_{x\to8}\left(4+3x\right)$

$a^2+11a\:+18$

$\left(\frac{3b^2}{a^{-2}}+\frac{a^{-3}}{b^{2n}}\right)^2$

$\sqrt{1+\left(x+1\right)\left(x-1\right)\left(x^2+1\right)\left(x^4+1\right)}$