$y'-x^3=x^3y$

$\:\int\frac{3\cos^3\left(x\right)-4\sin^3\left(x\right)}{\sin^2\left(x\right)\cos^2\left(x\right)}dx$

$\frac{x-10}{x^24x+2}$

$2\sin\left(2a-\frac{\pi}{5}\right)+2\cos\left(2a\right)$

$\left(3s^5+8t^{12}\right)\left(3s^5-8t^{12}\right)$

$-66\left(5\right)$

$\frac{2x^2+16x+25}{x+6}$