$x^2-8x+16=\left(x-4\right)^2$
$f\left(x\right)=\tan\left(3x-3x\right)$
$\lim_{x\to5}\:\:\left(\frac{x^2-7x+10}{x^2-10x-8}\right)$
$x^3+2^2-x-2$
$-458-597.7$
$\left(3w\right)\left(w+4\right)\left(w-4\right)\left(x+x\right)$
$25+\left|-14\right|+3$
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