$\int\frac{3}{x}\left(ln\:x\right)^2dx$
$\frac{x-2}{3}<5$
$\left(4n^3+2\right)x\left(4n^3-2\right)$
$2sin\left(\theta\right)+\sqrt{2}=0$
$v\left(x\right)=\frac{2x}{\left(x+1\right)^2}$
$\int\frac{\left(x+8\right)}{\left(x^6-2x^4+x^2\right)}dx$
$-y^2=y-2$
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