$\left(2a^5b^3+\frac{1}{4}a^2b^2\right)^2$
$2y-2yx-3y^2=0$
$u^2+8u+64$
$\frac{a-b}{b-a}$
$3x^2-8x-3$
$79\:.\:51$
$\left(1+2\right)\left(+1\right)\left(-2\right)\left(+3\right)\left(-4+3\right)$
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