$5.800\:\:entre1.25$
$\left(2xy^4+x\right)dx+\left(4x^2y^3\right)dy=0$
$-5y+6y+9y-14y$
$\frac{\left(2x^2-4\right)}{x+5}$
$3+\frac{x^2}{x}$
$f\left(x\right)=\frac{-x\left(2x+1\right)^2}{\left(2^x\cdot\:2^3-2\right)}$
$\:4-2x=3x+14$
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