$\left(7x^3\right)\left(10u^3v^5\right)\left(8uv^3\right)$
$24-16+20+6-36+10$
$\left(m-8\right)\left(m-7\right)$
$\left(3x^3\right)\left(4x^5\right)$
$\frac{2x^3+3x-10}{x+3}$
$9\left(3x+7\right)-4\left(6x+7\right)-7$
$\frac{3}{x}-\frac{4}{x+2}$
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