$\frac{1}{x^2-6x+8}$
$\left(4x+5b\right)^3$
$\lim_{x\to\infty}\left(\frac{10-\sqrt{x}}{2+5\sqrt{x}}\right)$
$\frac{dx}{dt}=4x^2-16$
$\sqrt[5]{32\:x^{10}\:y^{15}\:z^{20}}$
$\lim_{x\to1}\frac{x\sqrt{x^2+1}}{x+1}$
$\int\:\:x^3\left(2-x^2\right)^2dx$
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