$100+80\cdot0,8^{\infty}$
$\frac{x^2-3x-4}{x-2}$
$3000+3000\cdot4\cdot20$
$\left(5br^2\right)^2$
$4x^2-5=30-20x$
$\log_{3x}\left(2x+1\right)=1$
$\int\:\:3^{x+1}dx$
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