$\left(x^5+3x^4-2x^3+6x^2-3x+4\right)-\left(-x^5+3x+4\right)$

$\lim_{x\to5}\left(\frac{sin\left(x-5\right)}{\left(x-5\right)^5}\right)$

$\frac{3x^3-2x^4-1-x^2}{x-2}$

$\frac{1}{z\left(z+1\right)}$

$1-\left[6-\left(46-4\right)-50+\left(42-16\right)\right]-3$

$2\sin\left(39\right)\cdot\sec\left(51\right)\cdot\cos\left(44\right)=1$

$65\infty$