$\frac{d}{dx}\left(x^3+x\right)\sqrt{6+x^3}$
$\frac{d}{dx}2x^2-6$
$x^4+3x^3-9x^2+5x$
$4a^3b^2+4a^2b^2$
$\sqrt{\sqrt{2}}.\sqrt[4]{2b^5}$
$\lim_{x\to\infty}\left(ln\left(x^5-1\right)-ln\left(x^3-1\right)\right)$
$16x^2-48x+9$
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