$\frac{\left(15x^5-12x^4+3x^3-4x^2+3\right)}{x-3}$
$\frac{dp}{dt}=t$
$9x^2-3x-5+5x-9$
$\frac{x}{c-2}=cx+4$
$\:\:20\:+\:15\:+\:40\:+\:\left(-12\right)\:+\:\left(-30\right)$
$\frac{dy}{dx}=4xy\left(5+y\right)$
$\left(3a^2b+5ab^2\right)\left(3a^2b+5ab^2\right)$
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