$4x^2-16x-19$
$\frac{\tan\left(65\right)-\tan\left(-55\right)}{1+\tan\left(65\right)\tan\left(-55\right)}$
$\left(5m^3n\right)\left(8mn^3\right)+\left(6mn\right)\left(4m^2n^2\right)\left(mn\right)-7m^4n^4$
$x^3+2^3$
$z^8-i=0$
$25a^2+20a+1$
$\int3cdx$
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