$3x+1=\frac{6}{x+2}+2x$
$\frac{20x}{2x}$
$3x^2\left(x-3\right)$
$\cos\left(a\right)\left(\sec\left(a\right)-\cos\left(a\right)\right)=\sec\left(a\right)^2$
$4csc\left(x\right)-2\:=\:0$
$\left(y^{-1}+y^{-2}\right)\left(9y^{-3}-10y^{-4}\right)$
$\frac{dx}{dy}\cdot cosx=\frac{y}{lny}$
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