$6x^2+5x+3\cdot4x^3-3x-2$
$\left(1-\sin^2a\right)\sec\left(a\right)$
$\frac{-9y}{\:dx}=\frac{2x^3}{dy}$
$\left(x+6\right)^2-\left(x-2\right)^2$
$78-\left(-64\right)$
$(4r^2t-2y)^2$
$-32x^4+16x^2+8$
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