$64x^3-343$
$\left(\cot x-1\right)=1-tc$
$\left(9-3b\right)^2$
$\left(-2\right)\cdot7\cdot8\left(-1\right)\cdot\left(-3\right)$
$\lim_{x\to-\infty}\:\sqrt{x^2-x}-x$
$\left(-6-3\right)\cdot[4+2:\left(-6+7\right)]\cdot\left(2\cdot\left(-1\right)+2\right)$
$12x-3\ge42x+7$
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