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Simplify the quotient of powers $\frac{\left(4x^3\right)^2}{\left(-121x^5\right)^3}$

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Integral

$\int\frac{\left(4x^3\right)^2}{\left(-121x^5\right)^3}dx=1.13\times 10^{-6}x^{-8}+C_0$ See full solution

Main Topic: Quotient of Powers

The quotient of powers of same base is equivalent to the same base to the power of the difference of exponents: $\frac{a^m}{a^n}=a^{m-n}$.

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