$12-19-\left(12-8\right)+\left(-4\right)$
$\lim_{x\to\infty}\left(\frac{x^3+3x+1}{4ln\left(x+3\right)}\right)$
$4-\frac{9}{4}x^2$
$4\left(-3^2\right)^3$
$e^{2y}y'=x^2-6x$
$4x^2-1-6x^2+x+1$
$\lim_{x\to1}\left(\frac{x^2-3x+2}{x-2}\right)$
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