$-4cd^4;\:c=-3;\:d=2$

$\sqrt{1089}$

$\lim_{x\to\infty}\left(\frac{n+8}{n^2+11n+24}\right)$

$-8+\left(-2\right)-\left(-10\right)-2+\left|-3-\left(5-6-1\right)+2\right|$

$20+90+51-12-34$

$992^2$

$\:\frac{\tan\left(\theta\:\right)-\tan\left(\theta\:-x\right)}{1+\tan\left(\theta\:\right)\tan\left(\theta\:\:-x\right)}\:$