$-p^2\left(2p^4q^3r^2\right)^4$

$\frac{dy}{dx}=\left(1+e^{-y}\right)\cdot\frac{sin\left(x\right)}{1+cos\left(x\right)}$

$\frac{\left(x^6-64\right)}{\left(x^3+8\right)}$

$\frac{d}{dz}\left(z+1=-2y+\sqrt{z^2-x}\right)$

$\frac{1}{x^2}dx+\frac{1}{y^2}dy=0$

$\left(a-1\right)\left(a+12\right)$

$-a+b-c+8+2a-19-2c-3a-3-3b-3c$