$\left(a^{5}\right)^{3}\cdota^{5}$
$\left(2x^3+3y^2\right)\left(4x^6-6x^3y^2+9y^4\right)$
$\lim_{x\to0}\left(\frac{5}{x^4}-\frac{1}{x^2}\right)$
$\frac{10}{9}a^3m.\frac{15}{8}am$
$\frac{5^{23}}{5^{n}}$
$\frac{m^8+m^4-m^3}{m^5}$
$4a^2-6b^6$
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