$\frac{8y^8}{4y^5}$
$\csc^{2}x-\cot^{2}x$
$\left(cotx\left(sinx+cosx\right)\right)$
$csc\left(100\right)-sec\frac{5\pi}{4}$
$4-\left(-17\right)$
$sin4x=0$
$\frac{dx}{dy}=e^{-3x}$
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