$8x\cdot3x^5$
$\left(\frac{1}{2}x^2+3x\right)^3$
$\lim_{x\to\infty}\left(\frac{4x+3}{\ln\left(2+4e^x\right)}\right)$
$\lim_{x\to0}\left(\frac{\sqrt{t\:}}{x^2}\right)$
$4.\left(-3\right)+8:\:\left(-2\right)$
$\int_0^{0.5}\left(3e^{-0.2x}\right)dx$
$\int_1^1\sqrt[5]{x}dx$
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