$\int_0^t\left(\frac{x}{\sqrt{x+1}}\right)dx$
$\sqrt{ab}\cdot\sqrt[3]{a^2b^2}$
$\lim_{x\to1}\left(\frac{x^2-1}{x^3-2x+1}\right)$
$\left(3x^3-2y^2\right)\left(9x^6-6x^3y^2+4y^4\right)$
$\left(a^2\right)^6$
$-12-3-7+4-2+1+5$
$\int\frac{8}{\left(y-9\right)^3}dx$
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