$x\frac{dy}{dx}+3y=\cos\left(x\right)\:;y\left(1\right)=\:1$
$\tan^2\left(x\right)-\frac{7}{2}\tan\left(x\right)=-\frac{3}{2}$
$m^2+m+8$
$x+12=3x+20$
$\sqrt[3]{6^{12}}$
$-4\left(w+1\right)=8$
$\int\frac{1}{256+32y^2+y^4}dy$
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