$1-9a^2y^4$
$9x^2-15x+64$
$\frac{\sin\left(2x\right)}{2\tan\left(x\right)}$
$5\left(1+\cos x\right)\left(1-\cos x\right)=\sen^{2}x$
$6x^2-9x+15$
$\frac{x}{9-4x}+\frac{3x}{4x-9}$
$\int_1^3\left(\frac{e\frac{3}{x}}{x^2}\right)dx$
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